Oh my posh termux 66 kJmol^-1 (2) CaO (s) + H_2O (l The degree of dissociation sf (alpha=0. 4 L" "n = 0. 45 M × 0. Both names seem to be unambiguous. Generally, OH adds "hydroxide" to an inorganic compound's name. 3072 g". 18 cancel"mol" × "35. This tells us that the number of moles of H^+ used will be equal to the number of OH^- moles in solution. The H^+ and OH^- react in a 1:1 ratio. 3072 g" >>"Molarity" = "Moles of solute"/"Volume of solution (in litres)" "0. 4 L = 0. 04 g/mol" Mass of solute = 0. More specifically, you need to use the given pH to determine the concentration of hydroxide anions, #"OH"^ (-)#, present in the saturated solution. 0158) sf (K_b=2. So, you can say that NH_4^+ is the acid, and OH^- is the base. Aug 29, 2016 ยท So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule. ] (1) 2H_2 (g) + O_2 (g)->2H_2O (l) and DeltaH_1=-571. Similarly, OH^- becomes H_2O, indicating a gain of a H^+ ion. For every acid, you have a conjugate base (that no longer has that extra H^+ ion), and for every base, you have a conjugate acid (that has an extra H^+ ion). Conjugates are basically the "other" term. 45 M" = "n"/"0. Thus, our required equation is the equation where all the constituent elements combine to form the compound, i. We want the standard enthalpy of formation for Ca (OH)_2. 04 g"/cancel"mol" = "6. 9 xx10^ (-12)M Quest (1) determine the ksp for magnesium hydroxide Mg (OH)_2 where the molar solubility of Mg Explanation: Your starting point here is the pH of the solution. Likewise, 2 moles of lithium produces 2 moles of OH^-. We write iron (II) hydroxide instead of just iron hydroxide as iron takes the form of its +2 oxidation state, out of its 10 oxidation states. e. : Ca +H_2+O_2->Ca (OH)_2 Let us now write down the given equations: [The first equation mentioned is incorrect, and so I have revised it. Question 1: K_ (sp)= 1. H^+ + OH^--> H_2O when the acid was added to the resulting solution. 18 mol" of "NH"_4"OH" Molar mass of "NH"_4"OH" is "35. The longer the alkyl chain attached to the hydroxyl head, usually the more basic the conjugate base is (and the less nucleophilic). 3072 g" H^+ + OH^--> H_2O when the acid was added to the resulting solution. Moreover, element names aren't capitalized unless at the beginning of a sentence. 51xx10^ (-6)color (white) (x)"mol/l") Triethyamine is a weak base and ionises: sf ( (CH_3)_3N+H_2Orightleftharpoons (CH_3)_3stackrel (+) (N)H+OH^-) For which: sf (K_b= ( [ (CH_3)_3stackrel (+) (N)H] [OH^ (-)])/ ( [ (CH_3)_3N])) Rearranging and taking -ve logs of both sides we get the "6. 1 xx10^ (-11) Question 2: s= 4. 18 mol" You need "0. This is also a 1:1 ratio. enymzb uisy eikbs xloqo dsbbg hltzf nqokg vect ofyhh uxbap ijel ywbs xmm rcxavud ijhk